(2y^3+8y^2+1)+(3y^3-y-4)=

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Solution for (2y^3+8y^2+1)+(3y^3-y-4)= equation: 


Simplifying
(2y3 + 8y2 + 1) + (3y3 + -1y + -4) = 0

Reorder the terms:
(1 + 8y2 + 2y3) + (3y3 + -1y + -4) = 0

Remove parenthesis around (1 + 8y2 + 2y3)
1 + 8y2 + 2y3 + (3y3 + -1y + -4) = 0

Reorder the terms:
1 + 8y2 + 2y3 + (-4 + -1y + 3y3) = 0

Remove parenthesis around (-4 + -1y + 3y3)
1 + 8y2 + 2y3 + -4 + -1y + 3y3 = 0

Reorder the terms:
1 + -4 + -1y + 8y2 + 2y3 + 3y3 = 0

Combine like terms: 1 + -4 = -3
-3 + -1y + 8y2 + 2y3 + 3y3 = 0

Combine like terms: 2y3 + 3y3 = 5y3
-3 + -1y + 8y2 + 5y3 = 0

Solving
-3 + -1y + 8y2 + 5y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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